Others Maths Puzzle Numerical Ability

find the smallest value of N such that 10!/N is an odd integer

Read Solution (Total 1)

10!=1*2*3*...*10

10! = 2^8 * 3^4 * 5^2 *7

so, 10!/N will be odd for smallest N = 2^8
10 years agoHelpfull: Yes(0) No(0)

Others Other Question

what are the last two digits of 3^1997 Eight friends A, B, C, D, E, F, G and H are playing a game. The game involves many rounds initially all of them stand forming a circle according to the alphabetical order of their names in clockwise arrangement.

In each round exactly three players exchange their position and in a round one player can exchange his position only once. Nobody can exchange position with his adjacent players and so player can exchange position in two consecutive rounds.

38. Which players can possibly play the first round?

a. A, D, E

b. B, C, F

c. F, G, H

d. A, F, L

39. If the first round is played by B, G and E then which player cannot play in the third round?

a. F

b. B

c. C

d. A

40. If C, E and G played the first round then which of the following statements must be true?

I. Both F and D will play the second round.

II. Both F and D cannot play the third round.

III. Atleast one out of F and D cannot play the third round.

a. I only

b. II only

c. III only

d. I and II only

41. If H, B and E played the first round then anyone out of the following can play in the their round except:

a. G

b. A

c. C

d. F