If HOW+MUCH=POWER ,then what is the value of P+O+W+E+R?

• if anybody wants to answer such type of questions, clearly explain them.otherwise dont submit your answers
• 10 years agoHelpfull: Yes(32) No(0)
• 705
  +9837
  ------
  10542
  so P+O+W+E+R =1+0+5+4+2=12
  
• 10 years agoHelpfull: Yes(16) No(10)
• please guys explain this problem in detail......
• 10 years agoHelpfull: Yes(3) No(0)
• how to solve these type of questions??? it takes 2 much of time... there is any alternate solution for this??
• 10 years agoHelpfull: Yes(3) No(0)
• 702
  9537
  -------
  10249
  -------
  1+0+2+4+9=16
• 10 years agoHelpfull: Yes(2) No(8)
• Don't know exact solution but have this question answered by someone on this site only as reference while solving
  
  Apple+perl=graps then g+r+a+p+s ????
  Solution:
  65547
  +5074
  =70621
  
  7+0+6+2+1 =16.
  
  To solve these kind of problems there are some rules
  
  1. Every letter is unique digit.
  
  A P P L E
  + P R E L
  ------------
  G R A P S
  ------------
  
  1. As every letter is unique digit A is not equal to G.
  2. But Maximum carry that can be produced by two digits is 1
  3. So A+1=G
  4. As we have carry on the last column P+P must be greater than 10
  5. Let P=5. Then We will get R=0 (As P+P=10, 1 is a carry R=0)
  6. First column E+L=S, Second Column L+E=P. Adders(E,L) same in both, but Answers (S,P) are different. So definitely fist column generates carry.
  7. Let E=7, L=4 then S=1. L+E+1(carry)=12 we get P=2. One goes as carry to third column
  8. Third Column --> P(5)+R(0)=A(6)
  9. Last Column --> A(6)+1=G(7)
• 10 years agoHelpfull: Yes(2) No(2)
• HOW
  MUCH
  --------
  POWER
  
  Each alphabet represents an unique number. We have 0-9 as our numbers.
  By looking at the 5 digit answer by adding a 3 and a 4 digit number confirms us that P & O represents 1 and 0 respectively. No other choice is left.
  Now, we will see that addition of H and U will be greater than 9 us to carry over 1. Plus we have repetitions of W,O,H. Hence we will have same value for a particular alphabet everywhere.
  Keeping all constraints in mind, after solving, we will have only one solution.
  
  P=1, O=o, W=6, E=4, R=2, H=7, C=3,
  U=8.
  
  Hence p+o+w+e+r= 12
• 10 years agoHelpfull: Yes(2) No(4)
• refer to the link below for a well explained solution
  
  http://qa.campusgate.co.in/460/how-much-power-then-p-o-w-e-r
• 7 years agoHelpfull: Yes(1) No(0)
• H O W 8 0 5
  +M U C H 9 4 7 8
  ----------- ---------
  P O W E R 1 0 2 8 3
  
  so p+O+W+e+r=1+0+2+8+3=14
  is it possible to have two ans?
  its depend on options.
  
• 10 years agoHelpfull: Yes(0) No(9)
• 12 is correct
• 10 years agoHelpfull: Yes(0) No(0)
• HOW+MUCH=Power
  o=0,p=1,r=2,c=3,e=4,w=5,h=7,u=8,m=9
  so 1+0+5+4+2=12
• 10 years agoHelpfull: Yes(0) No(0)
• 805
  +9718
  -----
  10523 ....so answer=1+0+5+2+3=11
• 10 years agoHelpfull: Yes(0) No(1)