Infosys
Company
Numerical Ability
Clocks and Calendars
3 6 7 12 13 18 19 24 . .? What is next
Read Solution (Total 13)
-
- 3
3*2=6
3*2+1=7
3*4=12
3*4+1=13
3*6=18
3*6+1=19
3*8=24
3*8+1=25
3*10=30
3*10+1=31
so 25,30,31 will be ans - 10 years agoHelpfull: Yes(42) No(9)
- let's divide the series into two parts like
3 7 13 19 ?=alternate prime numbers 2 3 5 7 11 13 17 19 23 29 ans is =>29
6 12 18 24 ? = mul of 6 like 6 12 18 24 30 ans is =>30
ans is 29 30
- 10 years agoHelpfull: Yes(20) No(7)
- 3*2=6+1
3*4=12+1
3*6=18+1
3*8=24+1
3*10=30+1
so 25,31 will be the ans. - 10 years agoHelpfull: Yes(7) No(3)
- 3,6,7,12,13,18,19,24 ,...
prime number are placed between multiples of 3
3,(3*2),7,(3*4),13,(3*6),19,(3*8),29
so the ans is 29 - 10 years agoHelpfull: Yes(7) No(1)
- this is an INTERTWINED series formed out of 2 distinct series.
1st series - 3 7 13 19
2nd series - 6 12 18 24
For the 1st series, next term is - 29 (alternate primenos)
For the 2nd series, next term is - 30 (multiples of 6)
Ans -> 29 30 - 10 years agoHelpfull: Yes(5) No(0)
- 31 will be 11th number
after 25 there will be 30 - 10 years agoHelpfull: Yes(3) No(0)
- 25
7-3 = 4
13-7 = 6
19-13 = 6
25-19 = 6 - 10 years agoHelpfull: Yes(1) No(2)
- next no are 29 and 30.
Because there are two sequences..one is primeno's 3,7,13,19 where one prime no is left after a prime no. So next prime no will be 29.
other one is multiple of 6, 6,12,18,24,30 - 10 years agoHelpfull: Yes(1) No(0)
- the ans is 25, 30, 31 ,36, 37....
- 10 years agoHelpfull: Yes(1) No(0)
- 29
prime no.s 2 3 5 7 11 13 17 19 23 29
so 3 7 13 19 29 is the series of prime no.s
so ans is 29 - 10 years agoHelpfull: Yes(1) No(0)
- ANS:29
Take odd places are 3,7,13,19..these are prime numbers.....these are in alternate form so answer is 29 - 9 years agoHelpfull: Yes(1) No(0)
- What is 8th term
- 10 years agoHelpfull: Yes(0) No(2)
- 2nd dig is 6+1=7(3rd dig)
6*2=12(4th dig)+1=13(5th dig)
6*3=18(6th dig)+1=19(7th dig)
6*4=24(8th dig)+1=25(9th dig)
so answer is 25 - 10 years agoHelpfull: Yes(0) No(0)
Infosys Other Question