In a class, there are 9 students in which there are 5 boys and 4 girls. In a row, there will always a boy between any two girls. Find out how many such arrangement possible?

• -b-b-b-b-b-
  
  therefore , 6C4*4!*5!
• 10 years agoHelpfull: Yes(33) No(4)
• ANS: 5!*4!
  ARRANGEMENT : B G B G B G B G B
• 10 years agoHelpfull: Yes(16) No(12)
• first arrange the boys we can do it in 5! ways
  then arrange girls there will be six empty spaces out of which we have to select any 4 therefore 6c4 and girls can arrange themselves in 4! ways hence the total no of arrangements will be 5!*6c4*4!=43,200
• 10 years agoHelpfull: Yes(10) No(3)
• B G B G B G B G B==5!*4!
• 10 years agoHelpfull: Yes(4) No(1)
• first lets arrange the girls
  g_g_g_g
  this can be done in 4!ways
  now we have to fill the 3 empty spaces with 5boys which can be done in 5c3*3! ways
  so ans is 4!5c3*3!
• 10 years agoHelpfull: Yes(1) No(2)
• ans is 5!..
• 10 years agoHelpfull: Yes(0) No(27)
• the can be arranged in 4!*5!
• 10 years agoHelpfull: Yes(0) No(3)
• gbgbgbg
  
  4 girls can be arranged in 4! ways.
  3 boys (since each between two girls) in 5c3 *3! ways.
  therefore, ans is 5c3*3!*4!
• 10 years agoHelpfull: Yes(0) No(3)
• 4!*5! will be ans.
  
  B G B G B G B G B
  will be the order, now since 4 girls can be placed at 4 places therefore 4p4
  now 5 boys can be arranged in 5 places therefore 5p5
  
  = 4p4*5p5 = 4!*5!
• 10 years agoHelpfull: Yes(0) No(1)