George can do a piece of work in 8
hours. Paul can do the same work in
10 hours, Hari can do the same work
in 12 hours. George, paul and hari
start the same work at 9 am, while
george stops at 11 am, the remaining
two complete the work.
What time will the work complete?

• 1.05pm work will complete
• 10 years agoHelpfull: Yes(7) No(0)
• 1.09pm work will complete
• 10 years agoHelpfull: Yes(6) No(0)
• take total work unit:120(l.c.m of 8,10,12)
  george=>120/8=15units,paul=>120/10=12units,hari=>120/12=10units.
  first two hours all the three members are worked.so,
  =>2(15+12+10)
  =>74
  =>remaining=120-74=46
  =>46/(12+10)
  =>appr 2 hours
  so the work will be completed at 1 pm.
• 10 years agoHelpfull: Yes(3) No(0)
• ans is 1.09
  
  let the total unit of work be 120
  now
  george can complete a work in 8 hour
  it means he does 15 units work per hour . ( AS 8*15= 120)
  SIMILARLY
  paul does 12 unit of work per hour . ( AS 10*12=120)
  AND hari does 10 units of work per hour .
  now
  G+P+H does 15+12+10 = 37 UNITS OF WORK PER HOUR
  
  G+P+H WORKS FOR 2 HOURS AND AFTER THAT GEORGE STOP WORKING
  THEY WORK FOR 2 HOURS (9.00 AM TO 11.00 AM ) that is THEY COMPLETE 37*2 (74) UNIT OF WORK
  
  TOTAL WORK =120
  REMAINING WORK 120-74=46
  NOW P+H DOES THE REMAINING 46 UNIT OF WORK
  P+H= 22 UNIT OF WORK PER HOUR
  
  NOW , TIME = 46 UNIT OF WORK DIVIDED BY 22 UNIT OF WORK PER HOUR
  46/22 = 2 2/22 THAT IS 2 1/11 = 2.09
  
  HENCE TOTAL TIME = 2 HRS + 2 HRS + 0.9 = 4.09
  
  FROM 9:00 AM + 4 HRS + .09 MIN === 1.09 PM ..
  
• 10 years agoHelpfull: Yes(2) No(0)
• can anybody xpln it clearly
  
• 10 years agoHelpfull: Yes(0) No(0)