how many four digit number can be formed using 2,3,5,6,7 and 8
which is divisible by 25.

• the number will be 25 and 75 in last digit
  so for 25 as last digit= 4*3*1*1=12
  for 75 as a last two digit= 4*3*1*1= 12
  so, 12+12=24
  
  ans=24
• 10 years agoHelpfull: Yes(34) No(0)
• the no in last degit shuld be (00, 25, 50, 75) which is divisible by 25
  but 0 is not persent so last digit(25, 75)
  then the selection of first digit is fix 5 =1
  then the selection of second digit is (2,7)=2
  then the selection of third and four digit is = 4*3
  so total no. of probability= 4*3*2*1 = 24
  
• 10 years agoHelpfull: Yes(10) No(1)
• ques ye tha how many four digit can be formed using 2,3,4,5,6,7 only once divisible by 25
  a 12
  b 20
  c 24
  d 40
  
• 10 years agoHelpfull: Yes(4) No(0)
• Ans : 24
  
  For any number to be divided by 25, it should be ended with {25,50,75,100)...
  Here 0 is not in the list... so d possibilities are the numbers ended with (25 nd 75)
  
  if v take the no. to end with 25, the remaining 2 digits can be any 2 among {3,4,6,7} . so the possibities are 4!/2= 24/2= 12
  
  if v take the no. to end with 75, the remaining 2 digits can be any 2 among {2,3,4,6} . so the possibities are 4!/2= 24/2= 12
  
  so 12+12=24
  
• 10 years agoHelpfull: Yes(3) No(0)
• 24 ans nahi ho skta because 4375 divide 25 two times
• 10 years agoHelpfull: Yes(0) No(1)
• sorry its using 2,3,4,5,6,7
• 10 years agoHelpfull: Yes(0) No(0)
• ---5 the no will divisible by 25 if the last digit of the no must be 0 or 5. so first we fix the no 5 at fourth place of the no then we arrange the numbers at remaining three places out of six remaining number 6p3=!6/!6-3=60 ans
• 10 years agoHelpfull: Yes(0) No(3)
• the no which can be divided by 25 always have 5 at the end and ten digit should be either 2 or 7
  and the remaining palaces will be fill by 3,6,8
  so
  3*2*2*1=12 ans
• 10 years agoHelpfull: Yes(0) No(3)
• Its 24...try fixing last two digits by which can b only 25 n 75..
• 10 years agoHelpfull: Yes(0) No(0)
• sry sryyy... if it is using 2,3,4,5,6,7 then
  last two positions= 2 ways
  remaining places = 6*6(repetition allowed)
  so total no.of way= 2*6*6=72
• 10 years agoHelpfull: Yes(0) No(1)
• first luck for the divisibility of 25...
  no will be. _ _ _ _ 5
  _ _ _ 7 5
  now three place can we fill in 4*3*2 way....ans is 24
  
• 10 years agoHelpfull: Yes(0) No(0)
• two nos will be divisible by 25; 25,75.
  --(25or75) then 4p2*2p1=24
  
• 10 years agoHelpfull: Yes(0) No(0)