TCS Company Numerical Ability

A runs 1
2
⁄
3
times as fast as B. If A gives B a start of 80 m, how far must the winning
post be so that A and B might reach it at the same time?
A. 200 m
B. 270 m
C. 300 m
D. 160 m

Read Solution (Total 1)

as time is constant so s1/s2=d1/d2
5/3x/x=80+d/d
5/3d=80+d
solvind
d=120
so distance of winning spot from a to reach there at same time=120+80=200
a is the answer
10 years agoHelpfull: Yes(5) No(0)

TCS Other Question

Department of Training & Placement
1.
A is 2
1
⁄
3
times as fast as B. If A gives B a start of 80 m, how long should the race
course be so that both of them reach at the same time?
A. 170 metre
B. 150 metre
C. 140 metre
D. 160 metre P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If
they can work together for 4 days, what is the fraction of work left?
A. 8/15
B.
7/15
C. 11/15
D.
2/11