A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance bet
ween them after 6 minutes ?
a)50 meter
b)100 meter
c)110 meter
d)None of above

• speed of thief = 10*5/18
  time = 6*60
  distance of thief = (10*5/18)*(6*60) + 200 = 1200m
  
  speed of policeman = 11*5/18
  time = 6*60
  distance of policeman = (11*5/18)*(6*60) = 1100m
  
  distance between both = 1200-1100 = 100m
  
• 10 years agoHelpfull: Yes(56) No(2)
• relative speed of thief and policeman=(11-10)=1km/hr
  Distance covered in 6 minutes = 6/60=1/10=100 m
  So distance between them after 6 minutes = 200 - 100
  = 100 m
  
  
• 10 years agoHelpfull: Yes(21) No(6)
• speed of police = 11 km per hr.
  speed of thief = 10 km per hr.
  so, relative speed of police = 1 km per hr.
  so,
  In 1 hr= 1 km
  60 min= 1000m
  1 min = 1000/60 m
  6 min = (100/6)*1m = 100m
• 10 years agoHelpfull: Yes(19) No(0)
• speed of thief=(10*1000)/60=500/3meter/min
  speed of police=(11*1000)/60=550/3meter/sec
  distance covered by police in 6minutes=(550*6)/3=1100meters
  distance covered by thief in 6 minutes=(500*6police covered 200 meters distance also.so after 200meters ,distance is=1100-200=900meters
  difference between them in 6 minutes is=1000-900=100meters
• 10 years agoHelpfull: Yes(1) No(0)
• for police dist in 6 minutes = 1100 meters at speed=11000 m/ 60 min.
  for thief dist in 6 minutes = 1000 meters at speed = 10000 m / 60 min.
  subtracting 1100-1000 = 100 meters
• 10 years agoHelpfull: Yes(1) No(0)
• b
  for theif-50/18*360=1000m
  forpolice-55/18*360-200=900m
  diff=100m
• 10 years agoHelpfull: Yes(0) No(0)
• the speed of the system is 1 km/hr
  the speed in m/sec will be 5/18 m/sec
  in 360 meter the distance covered is 5*360/18=100m
  therefore distance between them is 200-100 m=100 m
  
  the answer is 100 meter
• 10 years agoHelpfull: Yes(0) No(0)
• un suffisent data
  
• 10 years agoHelpfull: Yes(0) No(3)
• 1000mtr/60 min*6 min=100mtr
  ans=200-100=100mtr
• 10 years agoHelpfull: Yes(0) No(1)
• ans is 720m sod willl be the right ans
• 10 years agoHelpfull: Yes(0) No(2)
• Firstly, the distance between a thief and policeman=200 m.
  Relative speed between the thief and the policeman=(11-10)=1 km/hr.
  We shall now convert km/hr to m/min.
  So, 1 km/hr=1000/60 m/min=50/3 m/min.
  10 km/hr=10*1000/60=500/3 m/min.
  11 km/hr=11*1000/60=550/3 m/min.
  
  Now, time taken by the policeman to catch=200/(50/3)=200*3/50=12 min.
  Now, distance run by the thief=(500/3)*12=2000m
  And, distance run by the policeman=(550/3) * 12=2200m
  Difference of their distance in 12 minutes=2200-2000=200 m
  Therefore, the distance between them after 6 minutes =(1/2)* 200=100 m.
  Thus, the correct answer is b)100 meter.
• 5 years agoHelpfull: Yes(0) No(0)