TCS
Company
Numerical Ability
Sequence and Series
70 54 45 41
Read Solution (Total 13)
-
- 70-(4^2=16)=54
54-(3^2=9)=45
45-(2^2=4)=41
41-(1^2=1)=40 - 10 years agoHelpfull: Yes(23) No(1)
- 70-54=16 i.e. 4^2
54-45=9 i.e. 3^2
45-41=4 i.e. 2^2
so ne next will be 40
441-40=1 i.e. 1^2 - 10 years agoHelpfull: Yes(6) No(0)
- 70-54=16=4^2
54-45=9=3^2
45-41=4=2^2
41-40=1=1^2
so, ans=40 - 10 years agoHelpfull: Yes(2) No(0)
- 41 is a prime no.
so ans.41 - 10 years agoHelpfull: Yes(0) No(3)
- subtracting 4^2,3^2,2^2,consecutively and then last 1^2 , so answer is 41-1=40
- 10 years agoHelpfull: Yes(0) No(0)
- 40
square of 4 is minus from that of 1st and 2nde no.
square of 3 and that of 2 is minus from 3&@ and 2nd and 1st so square of 1 should be minus from 41 that is 1 +40 - 10 years agoHelpfull: Yes(0) No(0)
- ans: 1
70 54 45 41 40
16 9 4 1
4^2 3^2 2^2 1^2 - 10 years agoHelpfull: Yes(0) No(0)
- 70-54=16
54-45=9
45-41=4
41-40=1
therefore the answer is 40.
- 10 years agoHelpfull: Yes(0) No(0)
- answer is 40
70-4^2=54
54-3^2=45
45-2^2=41
41-1^2=40 - 10 years agoHelpfull: Yes(0) No(0)
- 70-54=16=4^2
54-45=9=3^2
45-41=4=2^2
41-40=1=1^2
the difference is the square value for each number starting from 4 decresing until 1 - 10 years agoHelpfull: Yes(0) No(0)
- 70-4^2=54
54-3^2=45
45-2^2=41
41-1^1=40 - 10 years agoHelpfull: Yes(0) No(0)
- Qus: 70, 54, 45, 41, ?
diff between two numbers is 16, 9, 4.
It is in the serious of 4^2, 3^2, 2^2, so next diff must comes in 1^2.
So, the next number is 40. - 10 years agoHelpfull: Yes(0) No(0)
- 70-54=16(4^2)
54-45=9(3^2)
45-41=4(2^2)
41-?+1(1^2) its 40 so ans 40 - 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question