A number consists of two digits whose sum is 9. The number obtained by reversing the order of the digits of the given number exceeds the given number by 27. Find the given number

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• 36
  3+6=9
  63-36=27
• 10 years agoHelpfull: Yes(1) No(1)
• a+b=9
  (10b+a)-(b+10a)=27
  9b-9a=27
  b-a=3
  b+a=9
  b=6
  a=3
  number is 36...
• 10 years agoHelpfull: Yes(1) No(1)