George can do a piece of work in 8 hours. Paul can do the same work in 10 hours, Hari can do the same work in 12 hours. George, paul and hari start the same work at 9 am, while george stops at 11 am, the remaining two complete the work. What time will the work complete?

• answer is 1.09 pm
  
  G-8hrs
  P-10hrs
  H-12hrs
  
  total work is LCM of 8,10,12 = 120
  hence G can do work in 15hrs
  P can do work in 12
  H can do work in 10
  
  initially G+P+H = 37 they work for 2 hrs hence 37*2= 74 of total work is completed
  therefore 120-74=46 is left now.
  P+H=22
  to complete 46 P+H have to do work for 22*2=44
  now 2 is left
  therefore 2/22=1/11
  hence the total time is 2+1/11=2.09hrs
  hence 11am+2.09= 1.09pm
• 10 years agoHelpfull: Yes(22) No(2)
• ((1/8)+(1/10)+(1/12))2+((1/10)+(1/12))(x-2)=1
  x=4 hrs
  work started at 9 am..
  takes 4 hrs to complete 9am + 4hrs =1:00 Pm
• 10 years agoHelpfull: Yes(6) No(2)
• Sry sry guyss Dont consider my previous ans
  
  Let the total work = 120 units.
  As George completes this entire work in 8 hours, his capacity is 15 units /hour
  Similarly, the capacity of paul is 12 units / hour
  the capacity of Hari is 10 units / hour
  All 3 started at 9 am and worked upto 11 am. So total work done upto 11 am = 2 x (15 + 12 + 10) = 74
  Remaining work = 120 - 74 = 46
  Now this work is to be done by paul and hari. 46 / (12 + 10) = 2 hours (approx)
  
  So work gets completed at 1 pm
• 10 years agoHelpfull: Yes(6) No(1)
• Ans is 1.09pm!
  G work in 1 hr = 1/8 or in 2hrs=1/4
  P work in 1 hr = 1/10 or in 2hrs=1/5
  H work in 1 hr = 1/12 or in 2hrs=1/6
  total work finished in first 2hrs = 1/4 + 1/5 + 1/6 = 37/60
  remaining work= 1- 37/60 = 23/60
  P and H work in 1 hr = 1/10 + 1/12
  then 23/60th work they can do in (10*12*23)/(22*60) = 2.09hrs
  So ans is 11am + 2.09hrs = 1.09pm!
  
• 10 years agoHelpfull: Yes(5) No(0)
• George do 100% work in 8 hrs so In 1 hr he do (100/8)% work =12.5%
  same as paul do (100/10)%=10% in 1 hr
  same for hari =(100/12)%=8.33%
  when they start together from 9am to 11am i.e 2hrs
  total work done: 2*12.5+2*10+2*8.33=61.66%
  reamining % work = 100-61.67%=38.33%
  now hari and paul both have to do 38.33% work
  remaining time require : 38.33/18.34= 2.08hrs
  so total time required : (2+2.08)hrs = 4.08hrs 4 hrs
• 10 years agoHelpfull: Yes(4) No(2)
• george,paul,hari 1 hour work is=1/8+1/10+12= 37/120
  george,paul,hari work together for 2 hours, so,george,paul,hari 2 hours work is: (37/120)*2=37/60
  remaining work=1-37/60=23/60 (23/60 work is done by paul and hari together)
  hari and paul 1 hour work is= 1/10+1/12=11/60
  23/60 hours work done by hari and paul= (11/60)* (60/23)=11/23
  so... ans is: 2(1/11)
  =2hr 5 mins
  so total time taken to complete the work is 2hr+2hr 5min= 4hr 5min
  work is started at 9 am
  so work is finished at 9am+4hr 5min=1pm and 5min
• 10 years agoHelpfull: Yes(4) No(0)
• 1 hour work when they work togather=1/8+1/12+1/10=37/120
  after 2 hour working of all=37*2/120=37/60
  remaing work=1-37/60=23/60
  p and h 1 hour work 1/10+1/12=11/60
  so no of days for p and h=60/23/60/11=11am+2.09= 1.09pm
• 10 years agoHelpfull: Yes(1) No(0)
• There is a small mathematical error , Please follow this
  
  (10+12+15)= 37*2 = 74 units of work is done
  
  Remaining = 120 - 74 = 46 units
  
  Therefore 46/ (10+12)= 46/22 = 2.0909.
  
  The total work done in 11.00am+ 2.0909 hours= 1.09 pm .
• 10 years agoHelpfull: Yes(1) No(0)
• Ans= 3.5 hr
  george, paul and hari;s 1 hr work= 1/8+1/10+1/12 = 37/120
  they worked for 2 hr
  therefore completed work= 2*37/120= 37/60
  therefore remaining work is 23/60
  now george stops work after 2 hr therefore one hours work= 1/10+1/120= 13/120
  and remaining work= 23/60
  therefore time required= (23/60) / (13/120) =(46/13)= approx 3.5 hr..
  
• 10 years agoHelpfull: Yes(0) No(1)
• answer is 1.55pm
• 10 years agoHelpfull: Yes(0) No(2)
• George completes the work in 8 hours
  Paul completes the work in 10 hours
  Hari completes the work in 12 hours
  
  L.C.M of 8,10,12 is 120, hence the total work to be done is 120 units
  
  G's efficiency = 120/8 = 15 units/hour
  P's efficiency = 120/10 =12 units/hour
  H's efficiency = 120/12 =10 units/hour
  
  i.e (10+12+15)*2 hours= 27*2 = 54 units of work is done
  
  Remaining = 120 - 54 = 66
  
  66/ (10+12)= 66/22= 3 hours.
  
  The work gets completed in 11.00am+ 3 hours = 1.00 pm !!
  
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• At 1.06pm
• 10 years agoHelpfull: Yes(0) No(3)
• 2/8+x(1/10+1/12)=1
  x(11/60)=1-1/4
  11x/60=3/4
  x=15*3//11
  x=45/11 or
  x=4 1/11
  45/11 is time taken by b and c to work together
• 10 years agoHelpfull: Yes(0) No(3)
• total unit of work is 120 unit
  george will do 15 unit in one hour
  paul will do in12unit
  hari will do 10 unit
  at 11 am 74unit work will be completed by all of them
  and the remaining work is 46 unit it will be done by hari and paul in 2.5 hours
  therefore the work will complete at 12:30 pm
• 5 years agoHelpfull: Yes(0) No(0)