CMAT
Exam
Numerical Ability
Permutation and Combination
in how many way can a selection be made of 5 letters out of 5As,4Bs,3Cs,2Ds,1Es?
a)70
b)71
c)15c5
d)15p5
Read Solution (Total 1)
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- 5 0 0 0 0 = 1
4 1 0 0 0 = 2C1*4C1 = 8
3 2 0 0 0 = 3C1*3C1 = 9
3 1 1 0 0 = 3C1*4C2 = 18
2 2 1 0 0 = 4C2*3C1 = 18
2 1 1 1 0 = 4C1*4C3 = 16
1 1 1 1 1 = 1
total = 1+8+9+18+18+16+1= 71
b)71 - 10 years agoHelpfull: Yes(1) No(0)
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