10. a + b + c + d = d + e + f + g = g + h + I = 17
Q.32 If a = 4, what are the values of d and g, each taken by only one of the digits from 1 to 9 ?

1) (2, 6)
2) (7, 1)
3) (9, 8)
4) (5, 1)

• a + b + c + d = d + e + f + g = g + h + I = 17
  
  a + b + c + d + d + e + f + g + g + h + I = 17 + 17 + 17 = 51 ---(1)
  
  but a+b+c+d+e+f+g+h+i = 45 [sum of 1+2+3+...+9] ----(2)
  
  (1)-(2) => d+g=51-45=6
  so, (d,g) may be (1,5),(2,4)or(3,3) but (2,4) & (3,3) are not possible as a=4 & from a to i , all are different
  
  so, (d,g)=(1,5) or (5,1)
  
  4) (5, 1)
• 10 years agoHelpfull: Yes(87) No(2)
• if a=4 and d=5,
  b+c=17-9=8=2+6
  g=1
  e+f=17-6=11=8+3
  h+i=17-1=16=9+7
  hence (d,g)=(5,1)
• 10 years agoHelpfull: Yes(3) No(0)
• Pls while typing the question, type properly.
  it becomes very difficult to understand sometimes.
• 10 years agoHelpfull: Yes(2) No(0)
• (7,1)
  a=4,b=5,c=3,d=8:a+b+c+d=17
  d=8,e=2,f=6,g=1:d+e+f+g=17
  g=1,h=7,i=9:g+h+i=17
• 10 years agoHelpfull: Yes(0) No(8)
• 4+6+2+5=5+3+8+1=1+7+9(d=5, g=1)
  
• 10 years agoHelpfull: Yes(0) No(0)