Q). A Programmer noted the results of attempting to run 20 programs. The results that 2 programs run correctly in the first attempt, 7 programs run correctly in the second attempt, 5 programs run correctly in the third attempt, 4 programs run correctly in the fourth attempt and 2 programs run correctly in the fifth attempt. What is the probability that this next program will run correctly on the third run ?

1) 1⁄4
2) 1⁄3
3) 1⁄6
4) 1⁄5

• prob. for 1st attempt=2/20=1/10
  prob. for 2nd attempt=7/18
  prob. for 3rd attempt=5/11
  so,prob. of next program will run
  =(prob of not run in 1st attempt)(prob of not run in 2nd attempt)(prob of run in 3rd attempt)
  =(1-(1/10))(1-(7/18))(5/11)
  =(9/10)(11/18)(5/11)
  =1/4 (option 1)
• 10 years agoHelpfull: Yes(27) No(0)
• probability for first attempt is 2/20 = 1/10
  probability for second attempt is 7/18
  so the probability for third attempt will be 1- (1/10 + 7/18) = 1/5 (ans-4)
• 10 years agoHelpfull: Yes(21) No(38)
• plzz giv me d crct sltn plzz
• 10 years agoHelpfull: Yes(10) No(1)
• Total 20 .
  So in 3rd run it will have 5/20= 1/4
• 10 years agoHelpfull: Yes(6) No(13)