entry ticket to an exhibition ranges from 1p to 31p.you need to provide exact change at the cointet.uot habe 31p coin.in how many [parts wil u divide 31p so that u will provide the exact change required and carry as less coins as ossible?

• Divide 31p into 5 parts such as 16p,8p,4p,2p,1p.
  So we can provide Exact change at the counter.i.e
  1p for 1p(if the ticket is 1p .
  2p for 2p.//if the ticket is 2p
  1p and 2p for 3p // if the ticket is 3p
  4p for 4p
  1p and 4p for 5p
  2p and 4p for 6p
  1p and 2p and 4p for 7p.....
  
  
  
• 10 years agoHelpfull: Yes(14) No(1)
• we will take 2^n ,where 2^n31 , so dnt take it
  let n=4
  2^4=16 which is less than 31
  
  so our ans will be n+1=4+1 i.e 5 (ANS)
  2^0 2^1 2^2 2^3 2^4
  1 2 4 8 16
  
  so max 5 coins
• 10 years agoHelpfull: Yes(9) No(0)
• If the price of an item is decreased by 10% and then increased by 10%, the net effect on the price of the item is
• 10 years agoHelpfull: Yes(0) No(1)
• It is solved as:
  1*2*4*8*16=31
  Thus answer is 5 coins..
• 10 years agoHelpfull: Yes(0) No(2)