A number divided by 357 leaves 5 as remainder. If the number is divided by 17, what is the remainder?
a. 9
b. 3
c. 5
d. 7

• let x is divided by 357 & gives quotient y & remainder 5 ,then
  
  x=357*y+5
  now x is divided by 17
  x/17 = (357*y+5)/17 = (21y + 5/17) => rem = 5
  
  c.5
• 10 years agoHelpfull: Yes(48) No(3)
• c is the answer
  
  suppose 362 divided by 357 remainder is 5
  if we divide 362 by 17 remainder is still 5
  
  u can also check with 719
• 10 years agoHelpfull: Yes(5) No(3)
• Suppose a number is (357*3)+5=1076
  If it is divide by 17 the remainder will be 17
  So, in case of both 357 and 17 the remainder wil be 5...Because 357 is a dividend of 17
• 10 years agoHelpfull: Yes(3) No(0)
• since 357 is completely divisible 17 and 5 is less than 17..... when the no is divided by 17 it will also leave 5 as remainder.
  same as when 10 divided by 9 leaves 1 as remainder and so does 10 divided by 3.
  ans.c(5)
• 10 years agoHelpfull: Yes(3) No(0)
• @RAKESH
  hows that ??
  (21y + 5/17) => rem = 5
• 9 years agoHelpfull: Yes(1) No(2)
• X/357 - REMAINDER=5
  X/17- REMAINDER=?
  since,357 is completely divisible by 17, so any no divisible by 17 gives remainder 5.
  ans=5
• 9 years agoHelpfull: Yes(0) No(0)
• 370k+5
  = (17*21)k+(17-10)-2
• 8 years agoHelpfull: Yes(0) No(0)
• 370k+5
  = (17*21)k+(17-10)-2
• 8 years agoHelpfull: Yes(0) No(0)