TCS
Company
Numerical Ability
Number System
A number divided by 357 leaves 5 as remainder. If the number is divided by 17, what is the remainder?
a. 9
b. 3
c. 5
d. 7
Read Solution (Total 8)
-
- let x is divided by 357 & gives quotient y & remainder 5 ,then
x=357*y+5
now x is divided by 17
x/17 = (357*y+5)/17 = (21y + 5/17) => rem = 5
c.5 - 10 years agoHelpfull: Yes(48) No(3)
- c is the answer
suppose 362 divided by 357 remainder is 5
if we divide 362 by 17 remainder is still 5
u can also check with 719 - 10 years agoHelpfull: Yes(5) No(3)
- Suppose a number is (357*3)+5=1076
If it is divide by 17 the remainder will be 17
So, in case of both 357 and 17 the remainder wil be 5...Because 357 is a dividend of 17 - 10 years agoHelpfull: Yes(3) No(0)
- since 357 is completely divisible 17 and 5 is less than 17..... when the no is divided by 17 it will also leave 5 as remainder.
same as when 10 divided by 9 leaves 1 as remainder and so does 10 divided by 3.
ans.c(5) - 10 years agoHelpfull: Yes(3) No(0)
- @RAKESH
hows that ??
(21y + 5/17) => rem = 5 - 10 years agoHelpfull: Yes(1) No(2)
- X/357 - REMAINDER=5
X/17- REMAINDER=?
since,357 is completely divisible by 17, so any no divisible by 17 gives remainder 5.
ans=5 - 10 years agoHelpfull: Yes(0) No(0)
- 370k+5
= (17*21)k+(17-10)-2 - 9 years agoHelpfull: Yes(0) No(0)
- 370k+5
= (17*21)k+(17-10)-2 - 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question