The age of the two friends were in the ration of 2:3.If the sum of their ages is 55.Then after how many years
their ratio will become 4:5?

• their current ages are
  2/(2+3) *55 = 22 & 3/(2+3) *55 = 33
  
  let after t years ratio of ages becomes 4:5, then
  
  (22+t)/(33+t)= 4/5 => t = 22 years
• 10 years agoHelpfull: Yes(26) No(1)
• current age : 22+33=55 2:3
  
  after 22 years 22+22:33+22=>44:55 4:5
• 10 years agoHelpfull: Yes(5) No(0)
• ans: 22 years
  explanation: let a:b=2:3 => a=(2b/3)
  given a+b=55
  => (2b/3)+b=55
  solving above eqn we get b=33 ,a=22
  Now let after x years their ages be in ratio 4:5
  => (a+x):(b+x)=4:5
  (22+x):(33+x)=4:5
  by solving for x we get 22 years
• 10 years agoHelpfull: Yes(3) No(0)
• let ages are: 2x & 3x
  then 2x+3x=55 (given)
  5x=55 => x=11
  so, age ratiois 22:33
  now (22+x)/(33+x)= 4/5
  by solving it: x= 22 yrs (Ans)
• 10 years agoHelpfull: Yes(3) No(0)
• 22 years after
• 10 years agoHelpfull: Yes(1) No(0)
• ans 22 years
  ratio 2 : 3 = 22 : 33
  ratio 4 : 5 = 44 : 55
  after 44 - 22 = 22 years
• 10 years agoHelpfull: Yes(1) No(2)
• current ages will be (2*55)/5 & (3*55)/5 i.e. 22 & 33
  now let after x years their ages will be in ratio 4:5,then
  22+t/33+t=4/5
  on calculating t=22 years
• 10 years agoHelpfull: Yes(1) No(0)
• 2x:3x
  2x+3x=55
  x=11
  present ages are 22 & 33
  after 22 years their ages will become in the ratio4:5(44:55)
• 10 years agoHelpfull: Yes(0) No(0)
• 2k+3k=55
  5k=55
  k=11
  22+x/33+x=4/5
  x=22
  after 22 years ages are 44/55=4:5 ans
• 10 years agoHelpfull: Yes(0) No(0)
• x+y=55
  2x=3y
  by solving we get
  y=22,x=33
  after 22 years their age will be in 4:5
• 10 years agoHelpfull: Yes(0) No(0)
• 2:3 55
  4:5 ?
  
  55*4:5 55*4*3
  ----------- = ---------- = 66
  2:3 5*2
• 9 years agoHelpfull: Yes(0) No(0)