If A's age is 4 yrs more than B's age and 2 yrs more than C's age. After 2 yrs A's age will be twice of B's age. Then find the current ages of A,B & C

• A=(B+4)=(C+2) ----(1)
  
  after two years
  (A+2)=2*(B+2) [put,A=(B+4)]
  => B=2
  
  so, from(1) A=(B+4)=6 , C=(A-2)=4
  
  A=6 yrs, B=2 yrs, C=4 yrs
• 10 years agoHelpfull: Yes(43) No(2)
• A=B+4=C+2
  we can write B=A-4 & C=A-2
  AFTER 2 YEARS A+2=2(B+2)
  A+2=2(A-4+2)
  A+2=2A-4
  A=6
  B=2
  C=4
• 10 years agoHelpfull: Yes(5) No(0)
• A = 6
  B = 2
  C = 4
• 10 years agoHelpfull: Yes(1) No(0)
• 6,2,4
  2+4=6
  2(2+2)=6+2
  6-2=4
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• What was ur approach ??
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• A=B+4=C+2
  A+2=2B
  ON Solving first and second equation
  a=6 ;b=2 ;c=4
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• age of b =x
  age of a=x+4
  age of c=x+2
  aftr 2 yrs:x+6=2(x+2)
  x=2(b's age)
  a's age=6
  c's age=4
• 10 years agoHelpfull: Yes(0) No(0)
• we get a=b+4 and a=c+2
  after two years a+2=2(b+2)==>a-2b=2 we hav a=b+4 solving this two we get a=6,b=2
  substituing in a=c+2 we get c=4
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• a=6 b=2 c=4
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• a=b+4
  a=c+2
  after 2 year
  b+4+2=2(b+2)
  b=1
  a=5
  c=3
• 10 years agoHelpfull: Yes(0) No(1)