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Numerical Ability
Quadratic Equations
if p(x)=ax^5+bx^4
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- i think question is incomplete..
- 10 years agoHelpfull: Yes(9) No(0)
p(x)=ax^5+bx^4
=x^4(ax+b)
if we take p(x)=0
then ax+b=0
i.e ax=-b
so x=-(b/a)
- 9 years agoHelpfull: Yes(1) No(0)
- kindly provide proper and complete questions .
- 10 years agoHelpfull: Yes(0) No(0)
- kindly provide proper question.
- 10 years agoHelpfull: Yes(0) No(0)
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