Two people, Ranbir and Katrina decide to meet at a a beach between 1 pm to 2 pm, given that both will surely turn up once in the given time frame. If Ranbir arrives, he waits for 15 minutes and then leaves feeling betrayed and similarly Katrina waits for 15 minutes after she arrives. So what's the probability that they meet?

• Total cases=60
  Favourable cases=15
  Prob=15/60=0.25
• 10 years agoHelpfull: Yes(38) No(1)
• I think answer is :7/16
  because probability that ranbir will not meet is 45/60=3/4
  same for katrina i.e 3/4
  
  so probability that they will meet is:
  1-[(3/4)*(3/4)]=7/16
  
  If i am wrong provide correct answer
• 10 years agoHelpfull: Yes(21) No(0)
• waiting time of both katrina and runbir is 15 min. Means they can meet only meet each other in 15 Min. , if they 1 more min. than they can't meet each other .. so chances of meeting in only(Favourable event )=15 min
  Total no. of min.(Sample space)= 60 min
  Probability of Meeting is =(Favourable event)/(Sample space)
  15/60=0.25 ans.
• 10 years agoHelpfull: Yes(18) No(3)
• Case-I: A arrives first
  If A arrives in the interval 12:00 to 12:45, then B must arrive within 15 minutes of A’s arrival. The probability of meeting can be found out by considering double definite integral, with limits (0 to 45) and (x to x+15). The probability density for each A and B is 1/60 and 1/60 respectively. By considering these probability densities and finding out the integral under the above-mentioned limits, we get the probability in this part as 3/16.
  If A arrives in the interval 12:45 to 13:00, then B must arrive before 13:00. The probability of meeting can be found out by considering double definite integral, with limits (45 to 60) and (x to 60). By considering the probability densities (1/60 and 1/60 for each A and B) and finding out the integral under the above-mentioned limits, we get the probability in this part as 1/32.
  Summing up the two parts, the probability in the Case-I = 3/16 + 1/32 = 7/32
  Case-II: B arrives first
  Going by the same logic as mentioned in the Case-I, we get
  Probability in the Case-II = 7/32
  Summing up the two cases, the probability = 7/32 + 7/32 = 7/16
• 10 years agoHelpfull: Yes(14) No(11)
• when ranbir has left feeling betrayed....how they gonna meet...??? its 0..
• 10 years agoHelpfull: Yes(6) No(2)
• 7/16.Probability
• 10 years agoHelpfull: Yes(5) No(5)
• 0.5 is the probability
• 10 years agoHelpfull: Yes(4) No(3)
• answer is --> 1/4*1/4=1/16
• 10 years agoHelpfull: Yes(3) No(0)
• 7/16
  1-45/60*45/60
  
• 10 years agoHelpfull: Yes(2) No(2)
• They can meet only once in 15 minutes
  time interval between 1pm to 2pm is 60
  15/60=1/4
• 10 years agoHelpfull: Yes(2) No(0)
• 0.25 is the probability.
• 10 years agoHelpfull: Yes(1) No(4)
• how? ankit
  
• 10 years agoHelpfull: Yes(1) No(0)
• 0.5 is the sulution....
  
• 10 years agoHelpfull: Yes(1) No(2)
• 25487945 hsgudyghuj
• 10 years agoHelpfull: Yes(0) No(1)
• (total time)2-(time conditioned)2/(total time)2=(60)2-(15)2/(60)2
  
  meaning:(a)2==a^2
• 9 years agoHelpfull: Yes(0) No(0)
• Prob meet =
  ( Total time^2 - unfavtime ^2)/ total time ^2
  Here unfav time means ranbir wait 15 mint
  Katrina wait 15 mins so unifav is 30 minit
  Total time= 1pm to 2pm =60 min
  
  So soln
  (60^2 + 30^2)/ 60^^2
  =3/4
• 9 years agoHelpfull: Yes(0) No(0)
• 15/60+15/60=1/2 = .50
• 7 years agoHelpfull: Yes(0) No(0)