For a real number x int x denotes the integral part of x that is int x is the largest

50, up to int(1/2+49/100) we will get zero from int(1/2+50/100) we get 1 as answer
so summing frm there we get 50
10 years agoHelpfull: Yes(3) No(0)
Answer can be 49
10 years agoHelpfull: Yes(1) No(2)
it will be 50
10 years agoHelpfull: Yes(1) No(1)
All the terms will be ZERo hence ANS is 0
10 years agoHelpfull: Yes(0) No(2)
50
as the value from 1 to 49 will give the integer value0 so summation from int(1/2)....int(1/2+49/100) = 0
so from now onwards int(1/2+50/100)=1
int(1/2+50/100)......int(1/2+99/100)=50
10 years agoHelpfull: Yes(0) No(1)
50
as the value from 1 to 49 will give the integer value0 so summation from int(1/2)....int(1/2+49/100) = 0
from int(1/2)+int(1/2+1/100)+....int(1/2+49/100) each term is less than 1 so

int(1/2)+int(1/2+1/100)++....int(1/2+49/100) = 0

from int(1/2+50/100)+int(1/2+51/100)+...+int(1/2+99/100) ,each term has a value greater than 1 except int(1/2+50/100)= int(1)=1

from 50 to 99 each gives a value 1

int(1/2)+int(1/2+1/100)+int(1/2+2/100)... .int(1 /2+99/100)= 1+1+..+ 50 times

so from now onwards int(1/2+50/100)=1
int(1/2+50/100)......int(1/2+99/100)=50

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10 years agoHelpfull: Yes(0) No(1)
100
because each term will equalise to 1 and addind upto 100 times it would be equal to 100
10 years agoHelpfull: Yes(0) No(3)

: For a real number x, int (x) denotes the integral part of x, that is int(x) is the largest integer less than or equal to x. Thus int (1.2) = 1 and int (-2.4) = -3, The value of int(1/2)+int(1/2+1/100)+int(1/2+2/100)... .int(1 /2+99/100) is