Five men are living in a home. The average age of the five men before 5 years was 55. After P years, one new man aged 50 joins with others in the house which makes the average age 60. Find the value of P.


1) 4
2) 3
3) 2
4) 7

• total age of the five men before 5 years = 5*55 = 275 yrs
  
  after P years
  (275+5*5+5P+50)/6=60
  => 350 + 5P = 360
  => 5P=10
  => P=2
  
  3) 2 years
• 10 years agoHelpfull: Yes(50) No(2)
• let avg be A
  5 years back:
  A-25 /5 =55, A= 300, avg person is 60 yrs
  now after P years implies:
  ((300+5p)+50) /6 = 60
  thus p =2
• 10 years agoHelpfull: Yes(11) No(2)
• Ans is 2..Solve using the options
• 10 years agoHelpfull: Yes(4) No(0)
• before 5 yrs total age of 5 persons = 5*55=275
  now or total present AGE OF 5 PERSONS = 275+5*5=300
  AVERAGE AGE NOW IS = 300/5 = 60
  AFTER P YRS IF 6TH PERSON JOIN THEN
  AVERAGE AGE = [300+5P+50]/6
  60 = [300+5P+50]/6
  60*6=350+5P
  360-350=5P
  10=5P
  P=2
  
• 10 years agoHelpfull: Yes(4) No(0)
• Option - 2 sum of present age of 5 men is (55*5+5*5) 300 so after 2 years sum of their age is 300+2*5 = 310 person age 50 joins so total age will be 360 of 6 men so now avg is 60 (360÷6)..
• 10 years agoHelpfull: Yes(3) No(0)
• Let the present age of all people be a,b,c,d,e.
  5 years ago,
  [(a+b+c+d+e)-25]/5=55
  so (a+b+c+d+e)=300
  after p years, that means (p-5) years from now, new avg equation will be
  
  => {[(a+b+c+d+e)+5(p-5)]+ 50}/6=60
  => (a+b+c+d+e)+5(p-5)=360-50=310
  => 300+ 5(p-5)=310
  => 5(p-5)=10
  => p=7 years
  therefore,answer is option d) 7 years
• 10 years agoHelpfull: Yes(2) No(1)
• let m be the presents man age.
  before 5 years
  5(m-5)/5=55
  =>m=60
  after p years
  (5(m+p)+50)/6=60
  =>5p=360-350
  =>p=2
• 10 years agoHelpfull: Yes(1) No(0)
• the avg age of five men before 5 was 55. so the present total age is 55*5+5*5=300
  one new man joined and the avg becomes 60
  (300+5p+50)/6=60
  350+5p=360
  5p=10
  p=2
  
• 10 years agoHelpfull: Yes(1) No(0)
• total age 5 men=275
  after 7 year=275+5*7=310
  new man add=310+50=360
  avg become 360/6=60(true)
  
• 10 years agoHelpfull: Yes(1) No(0)
• Ans= 2
  
  5 year ago,
  sum of present age of five members -5*5=55*5
  so, sum of present age of of five members =300
  now
  after p years,
  sum of present age of five members +5*p+50 = 60*6
  or, 300+50+5*p=3600
  or, p=2
• 9 years agoHelpfull: Yes(1) No(0)
• 4
  5x-5=55*5
  after p yeras 5x+p+50=360
  4
• 10 years agoHelpfull: Yes(0) No(3)
• option 3 is correct
• 10 years agoHelpfull: Yes(0) No(0)
• total age before 5 hr of 5 men=55*5=275
  so at present total age of 5 men=275+5*5=300
  so now according to question
  (350+p)/6=60
  so p=2
• 10 years agoHelpfull: Yes(0) No(0)
• p = 2 years
  sum of ages 5 years ago = 55*5 = 275
  now atq 275+25+50+5p =60*6
• 10 years agoHelpfull: Yes(0) No(0)
• before 5 years total age of 5 men=55*5=275 yrs
  at present=275+25=300 yrs
  after p years
  (300+x+50)/6=60
  x=10
  so p=10/5=2
  3)2 years
• 10 years agoHelpfull: Yes(0) No(0)
• let a+b+c+d/5=55;a+b+c+d=5x55=275
  after p years a+b+c+d+25+5p+50/6=60
  so p=2 years
• 10 years agoHelpfull: Yes(0) No(0)
• 7
  dfdfdfasfasd
• 9 years agoHelpfull: Yes(0) No(1)
• Let the total age of 5 men be X.
  
  Then the average age of 5 men before 5 years = (X - number of years x number of men)
  
  / number of men = (X - 3x5)/5 = (X-15)/5 = 55
  
  Then X = 55 x 5 + 15 = 290. That is, presently the total age = 290.
  
  After P years, the total age of the 5 men becomes X + 5xP = 290 + 5xP.
  
  One man aged 50 joins with them. Therefore the average becomes (Total age of 5
  
  original men after P years + Age of new man) / Total number of men = (290 + 5P + 50)/
  
  (5+1) = 60
  
  or 5P = 360 - 340 = 20
  
  p = 20/5 = 4
  
  Therefore, 4 years is our required answer.
• 8 years agoHelpfull: Yes(0) No(0)
• 4
  don know
• 4 years agoHelpfull: Yes(0) No(0)
• 2 years will be the answer
• 4 years agoHelpfull: Yes(0) No(0)