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Numerical Ability
Arithmetic
1*1!+2*2!+3*3!+4*4!+.......+2012*2012!
Read Solution (Total 4)
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- answer is (2013!-1)
1*1!+2*2!=5->(3!-1)
here 5 can be converted like this so
1*1!+2*2!+3*3!=23->(4!-1)
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so we can write as 2012*2012!=2013!-1 - 10 years agoHelpfull: Yes(21) No(2)
- 1*1!=2!-1
1*1!+2*2!=1+4=3!-1
1*1!+2*2!+3*3!=1+4+18=23=4!-1
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Similarly, 1*1!+2*2!+3*3!+4*4!+.......+2012*2012!=2013!-1 - 10 years agoHelpfull: Yes(3) No(0)
- since it follows the pattern of 1*1!+2*2! = 3!-1so
ans would be 2013!-1
- 10 years agoHelpfull: Yes(0) No(0)
- Answer is 2013!-!
the general term of the above sequence is n*n!
which can also be written as ((n+1)-1)*n!
=(n+1)*n!-n!
= (n+1)!-n!
now according to the above equation
(2!-1!)+(3!-2!)+(4!-3!).......(2013!-2012!)
so the answer is
ans=(2013!-1!) - 10 years agoHelpfull: Yes(0) No(0)
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