The rectangle of height 100 squares and width 200 squares is drawn on a graph paper.It is colored square by square from top left corner and moving across in a spriral turning right whatever a side of the rectangle or a colored square is reached .Which square is colored last ( give its row and column number –the bottom right square is on row 100 and column 200)

• answer:51,50
• 10 years agoHelpfull: Yes(6) No(6)
• can anyone explain this solution.............
• 10 years agoHelpfull: Yes(5) No(0)
• row 51
  column 150
• 10 years agoHelpfull: Yes(4) No(3)
• Row - 51
  column - 100
• 10 years agoHelpfull: Yes(3) No(1)
• ans.row-50,column-100
• 10 years agoHelpfull: Yes(2) No(3)
• Length(height)=100 squares
  breadth(width)=200 squares
  (row,col)=((length/2+1),(breadth/4))
  =(100/2+1),(200/4)
  =51,50
• 6 years agoHelpfull: Yes(2) No(0)
• answer:51,150
  
  Let's take starting index as (1,1) and after first round of moving around in a spiral we reach (2,1).....
  
  After 1st round, we reach (2,1) , no. of rows and columns left to cover is (98,198)
  After 2nd round, we reach (3,2) , rows and columns left is (96,196)
  After 3rd round, we reach (4,3) , rows and columns left is (94,194)
  .
  .
  .
  So, we can observe a pattern here,after each round we reach (x+1,x) and we're left with (100-2*x,200-2*x) rows and columns respectively, so when x=50 ,(100-2*50,200-2*50)=(0,100)...So,we can infer that when we're at (51,50) we still have 100 columns left to cover,so after moving right by 100 columns we reach (51,150)
• 5 years agoHelpfull: Yes(0) No(0)