A bag contains 1100 tickets numbered 1,2,3,…..,1100,. If a ticket is drawn out of it at random , What is the probability that the ticket drawn at the digit 2 appearing on it?

• no of numbers having 2 in 1 to 100=19
  no of numbers having 2 in 101 to 199=19
  no of numbers having 2 in 200 to 299=100
  no of numbers having 2 in 300 to 1100=19*8
  so prob = (190+100)/1100= 290/1100 = 29/110
• 10 years agoHelpfull: Yes(63) No(29)
• hi friend in 1 to 100 ,no of numbers having 2 will be 20 because in 20 series it will be of 11 twos becos in 22 ,two times no 2 is repeated.
• 10 years agoHelpfull: Yes(8) No(9)
• no of 2's in 1 to 99=20,lly in a 101 to 199,
  200 to 299 =120,on sooon
  total no.of 2 in 1 to 1100 =300
  prob=300/1100=3/11
• 10 years agoHelpfull: Yes(6) No(8)
• no of 2's from 1 to 100 is 20
  no of 2's from 101 to 199 is 20
  no of 2's from 200 to 300 is 120
  no of 2's from 200 to 300 is 20
  and so on
  so total no of 2's b/w 1 to 1100 is 320
  so probability 320/1100=16/55
• 8 years agoHelpfull: Yes(5) No(4)
• no. of 2's in 1 to 1100 =300
  so if 1 ticket is drawn at random then the probability will be 300/1100=3/11
• 9 years agoHelpfull: Yes(4) No(5)
• 22,122,222,322.....922 are the single numbers. dont count 22, 2 times.
  karan ans is correct.
• 9 years agoHelpfull: Yes(2) No(5)
• probability=0.19
  no's digits appearinin on it is 19 frm 1 to 100
  then frm1,2,3......1100 =19*11=209
  probability = 209/1100=0.19
• 10 years agoHelpfull: Yes(0) No(17)
• Ans is 32/110=16/55
  1 to 999- digit wise counting
  three digit:
  so
  i) 2 as first digit so possibilities are in second and third are 10 which is =1*10*10=100
  ii) 2 as second digit so possibilities are in first and third are 10 which is =10*1*10=100
  iii) 2 as third digit so possibilities are in first and second are 10 which is =10*10*1=100
  then Now we consider 1000-1099
  2 is not appear in first two digit
  So i) 2 as third digit, possibilities of fourth digit is 10=1*1*1*10=10
  i) 2 as forth digit, possibilities of third digit is 10=1*1*10*1=10
  
  Finally total=100+100+100+10+10=320
  Probability=320/1100=32/110=16/55
• 7 years agoHelpfull: Yes(0) No(2)