What is the value of ((44444445*88888885*44444442+44444438)/44444444^2)

• (44444445*88888885*444444442+44444438)/44444444^2
  
  let x=44444444 then exp will be
  
  =((x+1)*(2x-3)*(x-2)+(x-6))/x^2
  =[(2x^2-x-3)(x-2)+(x-6))/x^2]
  =(2x^3-4x^2-x^2+2x-3x+6+x-6)/x^2
  =(2x^3-5x^2)/x^2
  =2x-5 [put the value of x]
  =2*44444444-5
  =88888888-5
  =88888883
  
• 10 years agoHelpfull: Yes(82) No(0)
• better use calculator in exam :P
• 10 years agoHelpfull: Yes(7) No(3)
• Let x = 44444444
  ((x+1)×(2x−3)×(x−2)+(x−6))/x^2
  ((x^2−x−2)×(2x−3)+(x−6))/x^2
  (2x^3−2x^2−4x−3x^2+3x+6+x−6)/x^2
  (2x^3−5x^2)/x^2=2x−5
  Substituting the value of x in 2x - 5, we get 88888883
• 10 years agoHelpfull: Yes(4) No(0)
• solve it answer is 88888883
  
  
• 10 years agoHelpfull: Yes(2) No(3)
• Let 44444444 = x
  (x+1)*(2x-3)*(x-2)+(x-6)
  x2
  (x2-x-2)(2x-3)+(x-6)
  x2
  2x3-2x2-4x-3x2+3x+6+x-6
  x2
  2x3-5x2 = 2x-5
  x2
  = 2(44444444)-5 = 88888883
• 10 years agoHelpfull: Yes(1) No(0)