A can do a work in 6 days , B can do a work in 8 days and C can do it in 12 days. B left work after 6 days. For how many number of days should A and C should work together to complete the remaining work ?

• i think one day.
  b work 1/8 * 6=3/4
  remaining work =1-3/4=1/4
  a and c work together =1/6+1/12=3/12=1/4
  take reciprocial 4 * remaining work =4 *1/4=1
• 10 years agoHelpfull: Yes(26) No(0)
• A complete work in 6 days
  B complete work in 8days
  C complete work in 12 days
  B's 1 day work=1/8
  6 day's work=6/8
  remaining work=1-6/8=2/8=1/4
  A+C 1 day work together = 1/6+1/12=1/4
  so A and C work 1 day to complete remaining work
  ans. 1 day
• 10 years agoHelpfull: Yes(20) No(0)
• lcm of 6,12,8 is 48 ie units
  a 1 day =8
  b 1day =6
  c 1day=4units
  3DAY WORK OF (A+B+C)=18
  6day work of (A+B+C)=36
  THUS REMAING WORK WILL IE 12 UNIT WILL BE COMPLETD BY AND C IN=12/12=1DAY
• 10 years agoHelpfull: Yes(4) No(0)
• 1/6+1/8+1/12=3/8
  3/8 work is done in 3 days
  therefore 1 day work = 1/8
  6day work = 3/4
  remaining work = 1-3/4
  1/4
  for 1/4 work no. of days required by 'A' 'C' is 1 day
• 10 years agoHelpfull: Yes(2) No(0)
• 1/6+1/12-1/8=8+4-6/48=1/8
  remaining the work:8*1/8=1 day
• 10 years agoHelpfull: Yes(2) No(2)
• my ans is 1 day
• 10 years agoHelpfull: Yes(1) No(1)
• b work is 6(1/8) means total 6days work is 6/8
  remaining work is 1-(6/8)=2/8
  that is 1/4 work remaining
  both a n c complete the work is 4(1/6+1/12)=1 day
  ans is 1day
• 10 years agoHelpfull: Yes(1) No(0)
• it will be 1
• 9 years agoHelpfull: Yes(1) No(0)
• 26 because A in 6 so B in 10 and C in 16
• 10 years agoHelpfull: Yes(0) No(9)