There are two shelves A and B.The number of books in shelf A is 50 more than in shelf B..Then 20 books are removed from each shelf..Then the number of books in shelf A is twice the number of books in shelf..what are the number of books in shelf A originally?

• books in a=50+x and b=x when 20 are removed 50+x-20=2(x-20) therefore x=70 and no of buks in A initially=50+70=120
• 10 years agoHelpfull: Yes(29) No(0)
• consider the books in B is x,then A has x+50,now 20 books are removed from both A&B then A has x+30,B has x-20,now books in A will be twice of books in shelf B
  so x+30=2(x-20) solve this eq gives x=70 so initially A has 120 books
• 10 years agoHelpfull: Yes(2) No(0)
• 120 is the answer for this
• 10 years agoHelpfull: Yes(1) No(0)
• 120 is the answer
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 120.
  let the no. of books in shelve A be'x' and no. of books in shelve B be 'y'.The two equations are :
  (i) x=50+y (ii) x-20=2(y-20)
  on solving the equations we get x=120 and y=70
  
• 10 years agoHelpfull: Yes(0) No(0)
• 120
  B has x A has X+50
  later B has x-20, & A has x+30
  given that x+30=2x-40
  x=70
  ==> x+50= 120
  :. A had 120 books initially
• 10 years agoHelpfull: Yes(0) No(0)
• a=50+b
  50+b-20=2(50)
  b=70
  a=120
• 10 years agoHelpfull: Yes(0) No(0)
• let number of books in shelf b be x then in a it will be x+50 .when 20 are removed from each then a has x+30 and b has x-20.acc to condition x+30=2(x-20) which gives x=70 .initially a has x+50=120.
• 10 years agoHelpfull: Yes(0) No(0)
• in a simple way:=
  x= 50+y
  (x-50)=2(y-50)
  sove these two equation:-
  got x=120 and y=70
• 10 years agoHelpfull: Yes(0) No(0)