TCS
Company
Numerical Ability
Time Distance and Speed
There was two trains from calcutta to kanyakumari one train is fast service travels with a speed 75km per hour another travels with a speed of 44km per hour the time taken to reach from calcutta to kanyakumari is 4hours less than the first train...find the distance b/w calcatta to kanyakumari
Read Solution (Total 18)
-
- let distance b/w calcutta to kanyakumari is = x km
then eqn is
x/44 - x/75 = 4
=> x*(75-44)=4*75*44
=> x = 425.8 km - 10 years agoHelpfull: Yes(63) No(0)
- dummy question!! how can slow service train take 4 hrs less than fast service train??
- 10 years agoHelpfull: Yes(17) No(5)
- let distance b/w calcutta to kanyakumari is = x km
then eqn is
x/55 - x/75 = 4
=> x*(75-55)=4*75*55
=> x = 825km
- 10 years agoHelpfull: Yes(8) No(8)
- Question was little incorrect.. correct 1 is below
There was two trains from calcutta to kanyakumari one train is fast service travels with a speed 75km per hour another travels with a speed of 55km per hour the time taken to reach from calcutta to kanyakumari is 4hours less than the first train...find the distance b/w calcatta to kanyakumari
- 10 years agoHelpfull: Yes(6) No(2)
- 75(t-4)=44t=d
=>t=300/31
d=44*300/31=425.8 kms - 10 years agoHelpfull: Yes(5) No(0)
- 4=d/55-d/55
solving this d= 825km - 10 years agoHelpfull: Yes(3) No(5)
- (d/44)-(d/75)=4
=> d=425.80 - 10 years agoHelpfull: Yes(2) No(0)
- ans is 825 km.
if the first train takes x hours then the second train will take x-4 hours.on equating the distance b/w 2 stations we get, 75x=55(x-4) hence x= 11 hrs. hence dist b/w stations is 75*11=825kms.
- 10 years agoHelpfull: Yes(2) No(1)
- wrong question.....
- 10 years agoHelpfull: Yes(1) No(1)
- How it is possible that train with slow speed(ie, @44km/hr) reach earlier(4hr less) than fast train which is running at 75Km/hr.
- 10 years agoHelpfull: Yes(1) No(0)
- how it is 55?
- 10 years agoHelpfull: Yes(0) No(0)
- cant be dtermined
- 10 years agoHelpfull: Yes(0) No(0)
- wrong question
- 10 years agoHelpfull: Yes(0) No(0)
- let distance b/w calcutta to kanyakumari is = x km
then eqn is
x/44 - x/75 = 4
=> x*(75-44)=4*75*44
=> x = 425.8 km - 10 years agoHelpfull: Yes(0) No(0)
- ans is x=425.8km
- 10 years agoHelpfull: Yes(0) No(0)
- (d/44)-(d/75)=4
x=425.8km - 10 years agoHelpfull: Yes(0) No(0)
- what is the correct answer??? plzz anyone tell...
- 10 years agoHelpfull: Yes(0) No(0)
- 825 is the right ans confirmed...
- 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question