a^2*b^2+a^2+b^2=259
b^2*c^2+b^2+c^2=1299
c^2*a^2+c^2+a^2=499
then find a+b+c=?

• put get a=3,b=5,c=7
  so a+b+c=15
• 10 years agoHelpfull: Yes(5) No(2)
• adding 1 to all equqtions.,we get them modified to the following form
  (a^2+1)(b^2+1)=260
  (b^2+1)(c^2+1)=1300
  (c^2+1)(a^2+1)=500
  by corresponding mul and div we get a=3,b=5,c=7
• 10 years agoHelpfull: Yes(1) No(0)
• ASSUME a=3 (since it is given that a,b,c are integers)and by substituting in the equations ,we get b=5 and c=7 ,hence a+b+c=15
• 10 years agoHelpfull: Yes(0) No(4)