25 Two dice are thrown simultaneously Find the probability of a The sum of the numbers appearing on the top

b) = 1/6
First dice can have any number and probability of getting same no on second dice is 1/6.
13 years agoHelpfull: Yes(7) No(1)
A) ANS : 5/36
B) ANS : 6/36=1/6
13 years agoHelpfull: Yes(1) No(0)
a) Prob. of getting the follwing combinations are as under
1,5(prob. is 1/6*1/6=1/36)
2,4(prob. is 1/36)
Similarly there are other combinations such as 3,3 4,2 5,1)
Hence the aggregate prob. that the sum of the nos. appearing on the top of the two dice being=5/36(1/36+1/36+1/36+1/36+1/36)
13 years agoHelpfull: Yes(1) No(0)
Just one correction to Answer of b:
Probabiltiy is 6*1/36=6/36 or 1/6
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b) The combination must be 1,1 2'2 3'3 4,4 5,5 and 6,6(six combinations)

Probability of getting each combination is 1/6*1/6=1/36
Thus the probability of getting all the combination taken together)=5*1/36=5/36
13 years agoHelpfull: Yes(0) No(0)
a) total no of outcomes will be = 36
possible no of outcomes will be as (1,5)(2,4)(3,3)(4,2)(5,10)=5
so the probability will be as =5/36

b) total no of outcomes will be=36
possible no of outcomes according to the question(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)=6
so the probability will be as=6/36=1/6
12 years agoHelpfull: Yes(0) No(0)

25. Two dice are thrown simultaneously. Find the probability of :

a) The sum of the numbers appearing on the top of the two dice being 6.
b) The numbers appearing on the top of both dice being same