125^n divides 325^325

• 325^325=(13*25)^325 = (13^325)*(5^650)
  125^n=5^(3n)
  power of 5 in numerator should be greater then denominator
  so 650>3n and hence
  n=216
• 10 years agoHelpfull: Yes(17) No(2)
• it may be 125 ...325^325= (13*25)^325 = (13^325)*(5^650)
  125^n = 5 ^ (3n)
  now we can say that to divide the value we can apply the value of n as
  3n < 650 so the value of n is less than 216 , it may be 125 ,100 ,150, 200 etc etc but in tcs 125 was an option
• 10 years agoHelpfull: Yes(4) No(0)
• can any one tell me how to handle this question
• 10 years agoHelpfull: Yes(4) No(1)
• Here, in 325 there are 2 5's and in 125 there are 3 5's.
  We need not to be concerned about the 13 in 325 as it is in numerator and 325^325 need to be divisible by 125^n.
  
  In 325 times 325 ,there are 650(325*2) 5's in denominator and they have to be divisible by 125^n
  So now we need 650/3=216 125.(as there are 3 5's in one 125)
  
  Now 125^216 is divides 325^325
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• 5^2010=6+3+0+1=1
  8^673=8(always fr odd powers)
  1*8=8
• 10 years agoHelpfull: Yes(0) No(2)