The dimensions of a certain machine are 48 32 52 if the size of the machine is increased proportionally until

Given dimensions of a machine are 48*32*52
if the size is raised proportionally untill the sum of dimensions
sum of given dimensions is 48+32+52=132
difference of actual and increased=156-132=24
24/3=8
this means each dimension has to raise for 8 units
thus the new dimensions are 56*40*60
10 years agoHelpfull: Yes(23) No(2)
48:32:52=12:8:13
156-132=24
24*(12/33)
24*(8/33)
24*(13/33)
10 years agoHelpfull: Yes(8) No(1)
Since it is proportionally,you have to,do it like this,
48x+32x+52x=156
132x=156
x=156/132,or x=13/11
therefore new dimension = 13/11*48 ,13/11*32,13/11*52
10 years agoHelpfull: Yes(3) No(0)
the actual question is......>>>
The dimensions of a certain machine are 48" X 30" X 52". If
the size of the machine is increased proportionately until
the sum of its dimensions equals 156", what will be the
increase in the shortest side?........

And the ans will be...
48+30+52=130.old dimension.
new dimension =156.
increse =26.
ratio of dimensions=48:30:52..=>24:15:26
15*(26)/(24+15+26)===6
7 years agoHelpfull: Yes(3) No(0)
what are new dimensions?(question continuation).
10 years agoHelpfull: Yes(2) No(0)
what is the qstn??
10 years agoHelpfull: Yes(1) No(3)
ya where is the Question???
10 years agoHelpfull: Yes(1) No(2)
http://www.geekinterview.com/question_details/5446
9 years agoHelpfull: Yes(1) No(0)

The dimensions of a certain machine are 483252,if the size of the machine is increased proportionally until sum of dimensions equals 156.