what is the average of series given as
1,-3,2,-4,3,-5...

• 1-3=-2
  2-4=-2
  3-5=-2...
  So average= -2-2-2....n/(2n)=-1
  Ans is -1
  
• 10 years agoHelpfull: Yes(28) No(1)
• 1+2+3-3-4-5= -6
  -6/6 =-1
• 9 years agoHelpfull: Yes(5) No(1)
• Incomplete question.....
  upto 2000 terms,,, what is the sum??
• 10 years agoHelpfull: Yes(4) No(4)
• 1-3=-2 sum of 2 numbers
  2-4=-2 sum of 2 numbers
  3-5=-2 sum of 2 numbers
  ........
  say there is a series of x then sum of x numbers is equal to (x/2)*-2
  and average will be
  ((x/2)*(-2))
  ------------
  x
  1/2*(-2)= -1
• 10 years agoHelpfull: Yes(2) No(1)
• 1-3=-2 sum of 2 numbers
  2-4=-2 sum of 2 numbers
  3-5=-2 sum of 2 numbers
  ........
  say there is a series of x then sum of x numbers is equal to (x/2)*-2
  and average will be
  ((x/2)*(-2))
  ------------
  x
  1/2*(-2)= -1
• 9 years agoHelpfull: Yes(1) No(1)
• Ans 4.
  
  It consists of series 1,2,3,.... (Numbers in odd places ) and -3,-4,-5,...(Numbers in even places).
  So the next number is 3+1=4
• 10 years agoHelpfull: Yes(0) No(20)
• 1-3=-2 sum of 2 numbers
  2-4=-2 sum of 2 numbers
  3-5=-2 sum of 2 numbers
  ........
  say there is a series of x then sum of x numbers is equal to (x/2)*-2
  and average will be
  ((x/2)*(-2))
  ------------
  x
  1/2*(-2)= -1
• 9 years agoHelpfull: Yes(0) No(0)
• 1-3=-2
  2-4=-2
  3-5=-2
  So the series is... -2-2-2....n times.
  So take -2 common .It gives -2(1+1+1......n times)=-2n
  average is =-2n/n(as n is the no of terms)=-2
• 9 years agoHelpfull: Yes(0) No(2)
• The answer is -1...
• 9 years agoHelpfull: Yes(0) No(0)
• -1 -1 -1 -1 -2
• 9 years agoHelpfull: Yes(0) No(0)
• 1-3=-2 average (-2/2) = -1
  1-3+2 = 0 average (0/3) = 0
  Therefore (1+(-3)+2+(-4)+3+(-5)+………n)/n = -1 / 0 [if n is even its -1 if odd then 0]
  
• 8 years agoHelpfull: Yes(0) No(0)