If a traveller was offered 5 city in asia and 11 city in europe and asked to chose atleast 3

no. of ways = 5C3*11C8 + 5C4*11C7 + 5C5*11C6=3762
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5c3*11c8 + 5c4*11c7 + 5c5 * 11c6 = 5610
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5c3*11c8+5c4*11c7+5c5*11c6=3762 ways
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no. of ways = 5C0*11C11 + 5C1*11C10 + 5C2*11C9 + 5C3*11C8

= 1 + 55 + 550 + 1650
= 2256
10 years agoHelpfull: Yes(3) No(28)
I think u r mistaken Gauranga. It won't be permutation as there is selection of cities and not arrangements (permutations)
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3762
as by rules of combination
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no. of ways = 5C3*11C8 + 5C4*11C7 + 5C5*11C6
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5C3*11C8+5C4*11C7+5C5*11C6=3762
10 years agoHelpfull: Yes(1) No(0)
ans is 4036
5C3*11C8 + 5C4*11C7 + 5C5*11C6
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atleast 3 cities are to be choosen from 5. so the man can choose

3 from asia and 8 from europe=5C3*11C8.
4 from asia and 7 from europe=5C4*11C7.
5from asia and 6 from europe=5C5*11C6.
so the answer is 5C3*11C8+5C4*11C7+5C5*11C6.
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all u jerks are wrong.
it'll be permutations.
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3762 ways
5c3*11c8+5c4*11c7+5c5*11c6
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(5c3*11c8)+(5c4*11c7)+(5c5*11c6)
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5C3*11C8+5C4*11C7+5C5*11C6
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(5c3*11c8)+(5c4*11c7)+(5c5*11c6)=3762
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3762 crrct
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If a traveller was offered 5 city in asia and 11 city in europe and asked to chose atleast 3 city in asia and overall a 11 city. How many ways can he travel