If a traveller was offered 5 city in asia and 11 city in europe and asked to chose atleast 3 city in asia and overall a 11 city. How many ways can he travel

• its right
  
  no. of ways = 5C3*11C8 + 5C4*11C7 + 5C5*11C6
• 10 years agoHelpfull: Yes(66) No(6)
• no. of ways = 5C3*11C8 + 5C4*11C7 + 5C5*11C6=3762
  
  
• 10 years agoHelpfull: Yes(16) No(0)
• 5c3*11c8 + 5c4*11c7 + 5c5 * 11c6 = 5610
• 10 years agoHelpfull: Yes(6) No(3)
• 5c3*11c8+5c4*11c7+5c5*11c6=3762 ways
• 10 years agoHelpfull: Yes(4) No(0)
• 
  no. of ways = 5C0*11C11 + 5C1*11C10 + 5C2*11C9 + 5C3*11C8
  
  = 1 + 55 + 550 + 1650
  = 2256
• 10 years agoHelpfull: Yes(3) No(28)
• I think u r mistaken Gauranga. It won't be permutation as there is selection of cities and not arrangements (permutations)
• 9 years agoHelpfull: Yes(2) No(0)
• 3762
  as by rules of combination
• 9 years agoHelpfull: Yes(1) No(0)
• no. of ways = 5C3*11C8 + 5C4*11C7 + 5C5*11C6
• 9 years agoHelpfull: Yes(1) No(0)
• 5C3*11C8+5C4*11C7+5C5*11C6=3762
• 9 years agoHelpfull: Yes(1) No(0)
• ans is 4036
  5C3*11C8 + 5C4*11C7 + 5C5*11C6
• 9 years agoHelpfull: Yes(1) No(1)
• atleast 3 cities are to be choosen from 5. so the man can choose
  
  3 from asia and 8 from europe=5C3*11C8.
  4 from asia and 7 from europe=5C4*11C7.
  5from asia and 6 from europe=5C5*11C6.
  so the answer is 5C3*11C8+5C4*11C7+5C5*11C6.
  
• 9 years agoHelpfull: Yes(1) No(0)
• all u jerks are wrong.
  it'll be permutations.
• 10 years agoHelpfull: Yes(0) No(7)
• 3762 ways
  5c3*11c8+5c4*11c7+5c5*11c6
• 9 years agoHelpfull: Yes(0) No(0)
• (5c3*11c8)+(5c4*11c7)+(5c5*11c6)
• 9 years agoHelpfull: Yes(0) No(0)
• 5C3*11C8+5C4*11C7+5C5*11C6
• 9 years agoHelpfull: Yes(0) No(0)
• (5c3*11c8)+(5c4*11c7)+(5c5*11c6)=3762
• 9 years agoHelpfull: Yes(0) No(0)
• 3762 crrct
• 8 years agoHelpfull: Yes(0) No(0)