TCS
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Numerical Ability
Sequence and Series
2,10,26,50.......
87 th no in the series
Read Solution (Total 4)
-
- 2,10,26,50......
(1^2+1),(3^2+1),(5^2+1),(7^2+1),....
Tn = (2n-1)^2+1
T87 = (2*87 -1)^2 + 1 = (173^2+1) = 29930
- 10 years agoHelpfull: Yes(57) No(3)
- sorry mine is wrong
- 10 years agoHelpfull: Yes(4) No(1)
- here
a=2
d=(n-1)*8 [means difference is 1*8, 2*8, 3*8 , etc...]
87th term= a+(n-1)d+(n-1)d
= a+2(n-1)d
=2+2(87-1)8
=2+2*86*8
=1378 - 10 years agoHelpfull: Yes(1) No(17)
- 1^2 +1=2
3^2+1+10
5^2+1=26
now 87th odd no. Tn=a+(n-1)d
1+(87-1)2
= 173
therefore; 173^2 +1=29930
- 10 years agoHelpfull: Yes(1) No(0)
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