5^2010
what will be the sum of digits?

• 5^2=25 sum of digits =2+5=7
  now if we take the power of 5 and do 2*3+1=7
  similarly for 5^4=625 and sum=6+2+5=13
  now do 4*3+1=13
  similarly, 5^2010 sum of the digits would be 2010*3+1=6031
• 10 years agoHelpfull: Yes(28) No(15)
• when power is even : 5^2=25 sum of digits =2+5=7
  now if we take the power of 5 and do 2*3+1=7
  when power is odd 5^9=1953125 sum of digits=1+9+5+3+1+2+5=26
  now do 9*3-1=26
  Similarly 5^2010 sum=2010*3+1=6031
• 10 years agoHelpfull: Yes(6) No(4)
• @zishan khan..the solution given by soumi singh is correct for powers which are even..try it for any power which is even d ans will be correct..but yes the question is wat to do wen poweris odd
• 10 years agoHelpfull: Yes(4) No(1)
• 5^2=25 sum of digits =2+5=7
  now if we take the power of 5 and do 2*3+1=7
  similarly for 5^4=625 and sum=6+2+5=13
  now do 4*3+1=13
  similarly, 5^2010 sum of the digits would be 2010*3+1=6031
• 10 years agoHelpfull: Yes(2) No(2)
• for 5^9=1953125
  sum of digits is 26
  according to your rule 9*3+1=28.
  
• 10 years agoHelpfull: Yes(1) No(1)
• the ans should be 6031 but method will be different.
  
  5^1=5
  5^2=25 sum of digits=7
  5^3=125 sum of digits=8
  5^4=625 sum of digits= 13
  and so on..
  if you look carefully then one pattern is definite
  that when the power of 5 is even then the sum of digits are increased by +6
  like 7,13,19 ..so on
  so as 2010 is even then in 2010/2=1005 th even number
  then 7+(1005-1)*6=6031
  so that is the answer.
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• Check your rule for 5^5
  5^5 = 3125
  i.e, 3+1+2+5 = 11
  
  
• 10 years agoHelpfull: Yes(0) No(1)