A, B, C, D are mid points of the rectangle. AB=10 cm. If one of the sides of the rectangle is 12 cm, what is the area of ABCD

• ABCD is a rhombus(A,B,C,D are the midpoints of rectange)
  area=1/2*d1*d2
  d1=12 (side of rectangle)
  d2=2*sqrt(10^2-6^2)
  =2*sqrt(64)
  =2*8=16
  area=96
• 10 years agoHelpfull: Yes(8) No(5)
• Joining the mid pt we get a rombos.
  one side is 12 cm.
  half of it is 6 cm.
  with that half and AB we get a right angle triangle.
  we get other side of rectangle by formula = 2*root(10Square-6square)=16
  so the area of rectangle is = 16*12 = 192
• 10 years agoHelpfull: Yes(7) No(5)
• Let, Rectangle is PQRS;
  PQ= 2*root of (100-36)=16
  PS=12(given)
  Area of PQRS= 16*12
  AREA OF ABCD= (16*12)/2= 96(Ans.)
• 10 years agoHelpfull: Yes(3) No(2)
• 
  get the other side of rectangle by formula 2*root(10^2-6^2)=16
  so the area of rectangle is = 16*12 = 192
• 10 years agoHelpfull: Yes(2) No(4)