A farmer sold two of his cows for 210/-. He sold one cow at a profit of 10% and other for a loss of 10%. Totally he gained 5% on selling both the cows. What is the original cost of each cow?
Option
a) 130 and 70
b) 150 and 50
c) 120 and 80
d) 115 and 85

• 150 and 50 is correct
  
• 10 years agoHelpfull: Yes(3) No(2)
• b 150 and 50
  10%150=15 10%50=5
  150+15=165 50-5=45
  165+45=210
  
• 10 years agoHelpfull: Yes(3) No(0)
• let cp of one cow is a and cp of other is b
  a+b=200
  sp of one cow =a*90/100....(1)
  sp of another cow=a*110/100....(2)
  (1)+(2)=210
  solving this we get a=50 b=150
  
• 10 years agoHelpfull: Yes(2) No(0)
• 1.05(CP1 + CP2) = 1.1CP1 + 0.9CP2
  Thus, CP1 = 3CP2
  Check options, no need to solve completely. SAVE TIME !!!!!
• 10 years agoHelpfull: Yes(2) No(0)
• it is a very easy problem,
  check by opp.
  let take opp b)
  sp1=150*(1+10/100) = 165
  
  sp2 = 50*(1-10/100) = 45
  
  now sp1 + sp2 =165 + 45 = 210 (which is equal to the given selling price).
  
  hence original cost prices are
  cp1=150
  cp2=50
  
  this is opp. based question. so do not go with lengthy process.
• 10 years agoHelpfull: Yes(1) No(0)
• hi mansi i cannot solve this. please explain
• 10 years agoHelpfull: Yes(0) No(0)