Ina competition A, B, and C are participating the probability that A wins in twice that of B. The probability that B wins in twice that of C. Then the probability that A loses in

• Suppose probability of wining C is x.
  So, B's wining probability= 2x and A's wining probability= 4x.
  We know, A's Probability + B's Probability + C's Probability=1
  Thus, x= 1/7.
  A's wining probability= 4/7. A's loosing probability= 1-4/7= 3/7.
  
• 10 years agoHelpfull: Yes(5) No(0)
• P(A)=2P(B) AND P(B)=2P(C)
  WE KNOW,P(A)+P(B)+P(C)=1
  THEREFORE,IF WE SUBSTITUTE THE VALUES WE GET P(A)=4/7.
  PROB.OF LOSING=1-(PROB OF WINNING)=1-(4/7)=3/7.
• 10 years agoHelpfull: Yes(2) No(0)