There are 600 pages there is 1 error on average per page what is the probability that there are n

This can be solved using a formula based from the Poisson distribution:

p = [ (λ ^ k)(e ^ -λ) ] / k!

Here, k = n, λ = 1, so p = (1^n) (e^-1) / n!

So the answer is

1
---------
(e) (n!)
10 years agoHelpfull: Yes(10) No(7)
According to Poisson distribution theorem,

Probability of n errors per page =1/(en!)
where e = 2.71828 and n! means n*(n-1)*(n-2) ... 1

So ,
For finding probabilty 0f 5 errors per page,
Answer: 1/(2.71828*5!)=1/(2.71828*120)
10 years agoHelpfull: Yes(5) No(2)
probability for the one error in page=1/600
prob. for the n errors in page=n/600.
so ans should be=n/600.
10 years agoHelpfull: Yes(1) No(28)
it is 11/36
10 years agoHelpfull: Yes(1) No(3)
You need higher math for this one, but I put it in because of how nifty the answer is. It turns out that the probability of n errors per page is 1/(en!) where e = 2.71828 and n! means n x (n-1) x (n-2) ... 1.

For example, the probability it zero errors per page is 1/e or 1/2.7, which is also the probabily of 1 error per page. The chance of 2 errors per page is half that and of 3 is 1(3x2) or 1/6 of the chance of 1. If you add up all of the possible probabilities of up to all 600 errors being on one page, the all add up to 1 (or very close to one. Technically, if you all them all the way to infinity, they add to one.)
9 years agoHelpfull: Yes(0) No(0)

There are 600 pages. there is 1 error on average per page. what is the probability that there are n errors per page.