Q 9. Given a quadratic equation, ax2+bx+c=0 If the ratio of the sum of the roots and the product of roots is 2:7, what can be possible values of b and c?

A. b=2,c=7

B. b=7,c=2

C. b=-2,c=-7

D. b=-2,c=7

• The given ratio of sum of roots and product of roots are 2:7
  sum of the roots= -b/a
  product of the roots= c/a
  
  (-b/a)/(c/a)=2/7
  therefore b:c= -2:7 i.e b=-2,c=7
• 10 years agoHelpfull: Yes(30) No(0)
• D.b=-2,c=7
  x^2 - (sum of the roots)x + (product of the roots) = 0
• 10 years agoHelpfull: Yes(2) No(0)
• ratio=sum/product
  =(-b/a)/(c/a)
  =-b/c=2/7
  hence,b=-2 and c=7.
  
• 10 years agoHelpfull: Yes(1) No(0)
• RATIO OF SUM OF ROOTS AND PRODUCT=2:7,
  SUM OF ROOTS=-B/A
  PRODUCT OF ROOT=C/A
  NOW
  RATIO=(-B/A)/(C/A)=2/7
  SO, -B/C=2/7
  SO THAT,B=-2 AND C=7
• 10 years agoHelpfull: Yes(1) No(0)
• given equation is ax2+bx+c=0
  so sum of the roots=-b/a
  product of the roots=c/a
  ratio is=(-b/a)/(c/a)
  
• 10 years agoHelpfull: Yes(0) No(0)
• -b/a=-2/7
  c/a=2/7
  (-2/7)/(2/7)=-1
  ans=-2,-7
  
• 10 years agoHelpfull: Yes(0) No(0)
• OPTION D SINCE SUM OF ROOTS IS -B/A AND PRODUCT OF ROOTS IS C/A -B/A:C/A=-B:C=2:7
  HENCE B=-2,C=7
• 8 years agoHelpfull: Yes(0) No(0)