Q 6 Rani s weight is 25 of Meena s weight and 40 of Tara s weight What percentage of

D. 160%
If Weight of Rani=R, Meena=M, Tara=T
Given,R=(25M/100)=(40T/100) or R=(M/4)=(2T/5), M=8T/5
% of Tara's weight to Meena's weight=100*8T/5=160
10 years agoHelpfull: Yes(30) No(1)

D.160%
Rani's weight=25% meera's weight = 40% tara's weight
meera's weight = 100/25*40% tara's weight
= 160% tara's weight
10 years agoHelpfull: Yes(10) No(0)
supose meena's weight= 200
so rani's weight is=(200*25)/100=50
so tara's weight is=(x*40)/100=50 =>x=125
tara' weight is meena's weight= (200/125)*100=160%
answer= D. 160%.
10 years agoHelpfull: Yes(7) No(0)
R=(M)*25/100=M/4
R=(T)*40/100=2T/5
M/4=2T/5
M=100*8T/5=160%
answer is D. 160%
10 years agoHelpfull: Yes(4) No(2)
Let Rani's weight be 100 kgs. Then, Meera's weight comes 400kgs. and Tara's weight is 250kgs.

Let "x" percent of Tara's weight be Meena's weight.
Implies: ( x / 100 ) * Tara's weight = Meena's weight.

Solve and you get answer is D. 160%.
10 years agoHelpfull: Yes(2) No(0)
given R=25%of M=40% of T
M/4=2T/5
M=8T/5
M=8*100/5% OF T
M=160% of T
ANS:D
9 years agoHelpfull: Yes(1) No(0)
D
R=1/4M
R=2/5T
M/T=8/5
M=160%T
9 years agoHelpfull: Yes(1) No(0)
Weight of meena = x, R= 25x/100=x/4
Let Tara's weight =y, R= 40y/100=2y/5
Now, x/4=2y/5.... x/y=8/5
8*100/5=160.....opt:D is correct....
5*
9 years agoHelpfull: Yes(1) No(0)
160% perfect
7 years agoHelpfull: Yes(0) No(0)
R=25% of M-----(1)
R=40% of T -----(2)
M=x% of T------(3)
Substitute (2) in (1) we get
40% of T = 25% of M
M=[(40/100)*(100/25) ]*T
M=1.6 T
M=160% of T [same as equation (3)]
6 years agoHelpfull: Yes(0) No(0)

Q 6. Rani's weight is 25% of Meena's weight and 40% of Tara's weight. What percentage of Tara's weight is Meena's weight?

A. 10%

B. 100%

C. 150%

D. 160%