In school there are some bicycles and 4 wheeler wagons.one Tuesday there are 190 wheels in the campus.How manu bicycles are there

• Answer is calculate using the options given in the answer..
  
  for example total wheels are 182 and options are a.20 b.19 c.18 d.16
  so we can possibility using the given values.
  a.---> 20*2=40--->182-40--->142--> for 4 wagons 142/4 is not possible so a is not true.
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  b.--->19*2=38--->182-38--->144--> for 4 wagons 144/4=36 is possible so b is true.
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  c.---->18*2=36--->182-36--->146--> for 4 wagons 146/4 is not possible so c is not true.
  d.---->16*2=32--->182-32--->150--> for 4 wagons 150/4 is not possible so d is not true.
  
  
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• tis questn has data insufficient
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• Data inadequate
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• this question can be solved if provided with options
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• data not sufficient
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• data insufficient
  
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• Let no. of bicycles be x
  & no. of wagons be y
  so, 2x+4y=190
  by solving, we get
  no. of bicycles=39 (wheels=>2*39=78)
  no. of wagons=28 (wheels=>4*28=112)
• 10 years agoHelpfull: Yes(2) No(4)
• taking equation as 4x+2y=190 then 2x+y=95 sub y=15 we get x=40 which satisfies the equation hence there are 15 bycycles and 40 wagons
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