TCS
Company
Numerical Ability
Time Distance and Speed
) A building with hight D ft shadow upto G A neighbor building with what height shadow C ft
is
Read Solution (Total 2)
-
- According to problem
D/G == C /X
X =CG/D(ans) - 12 years agoHelpfull: Yes(8) No(3)
- height of 1st building / shadow of 1st building = height of 2nd building / shadow of 2nd one
that is -- D/G = X/C
AND answer x=DC/G - 11 years agoHelpfull: Yes(1) No(0)
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