56 tofees have to divided into A,B,C,D,E so that each one gets minimum of ten toffees. find the no. of ways.

• n+r-1 C r-1 by this we'll get 6+5-1 C 5-1 = 10 C 4
• 10 years agoHelpfull: Yes(9) No(6)
• first we will distribute 10 toffees to each of 5 persons i.e total 50 toffees ,
  now remaining toffees are 6 which we have to distribute among 5 person so this can be possible in
  m+r-1 C r-1
  =>6+5-1C5-1=10C4
• 10 years agoHelpfull: Yes(6) No(1)
• ans 10 C 6
• 9 years agoHelpfull: Yes(3) No(1)
• shudnt it be 10C5...why r u taking n+r-1Cr-1.. why not n+r-1Cr
• 10 years agoHelpfull: Yes(1) No(1)
• all of u below are wrong.....sorry to say so....
  its like..a+10 +b+10........e+10 =56
  a+B....+E = 56-50 = 6
  ans will be...................................(N-1)C (R-1)
  6-1C 5-1 = 15ways ......esle wise also rohit use ur logics how can it be 210 ways to distribute if everyone already has 10....bestofluck
• 9 years agoHelpfull: Yes(0) No(0)