The sum of all possible two-digit numbers formed from three different one-digit natural numbers when divided by the sum of the original three numbers is equal to:
a)18
b)22
c)36
d)none of these

• Let the three no. be x,y,z
  
  So,the sum of all two digit no. formed by them is
  (10x+y), (10x+z), (10y+x), (10y+z), (10z+x), (10z+y)
  
  According to the Question;
  (10x+y) + (10x+z) + (10y+x) + (10y+z)+ (10z+x) + (10z+y) = 22(x+y+z)
  (x + y + z) = 22(x + y + z)
  
  22(x+y+z)/(x+y+z) = 22
  so answer will be 22
• 10 years agoHelpfull: Yes(3) No(1)