There are 8 teams(A,B,C.D,E,F,G,H) in a tournament. Each team will play exactly 2 games. How many matches are there to be played and give at least one possible solution set.?

• each team will play two match so set(ab ,bc ,cd,de,ef,fg,gh,ha)
  so A played two ab ,ha
  A played two ab ,ha
  B played two ab ,bc
  C played two bc ,cd
  and so on D,E,F,G,H played 2 games
  so final answer is total 8 games
  
• 10 years agoHelpfull: Yes(1) No(0)
• 1'st game:a(ab,ac,ad,ae,af,ag,ah),b(bc,bd,.....except ab),c(5),d(4),e(3),f(2),
  g(1),h(0), totally 28 matches
  2'nd game: a(...) same as above game, so totally 28 matches..
  
  sum of two games=28+28=56
  so 56 matches...
• 10 years agoHelpfull: Yes(0) No(3)
• there r 8 teams
  condition each team will paly exactly 2 games
  ie 8p2=>8!/(8-2)!
  8*7*6!/6!=56
• 10 years agoHelpfull: Yes(0) No(1)