There are 10 Letter and 10 correspondingly 10 different Address if the letter are put into envelope randomly then find

1/10!....if 9 goes in correct places then the one left will automatically be at its right place...so only one case possible ie all goes to right places.
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yes...anuj its zero..good keep it up
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ans is 0.
because if 9 letters are in correct address then the 10th letter will be automatically in correct address.
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Zero
Since if 9 letter are crrosponding to their respective envelop the 10th one will always be in right envelop . so there is no event of EXACTLY 9 letter at correct address
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correct answer is 0 bcz if 9 add is correct then 10th is automatically correct so,,answer is ZERO
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@ all of you bro
how can you assume 9 are correct address while letter is put into randomely
hence
explain it properly.
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Oh yes ANUJ...my bad...for 'exactly' 9 the probability is 0.
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ans: as we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address
p(r):favorable outcomes /total outcomes
here favorable outcomes are 0......so probability is 0
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Ans is 0. Bcoz when 9 letter are in correct address so automatically the 10 th will also go to the correct address
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There are 10 Letter and 10 correspondingly 10 different Address if the letter are put into envelope randomly then find the Probability that Exactly 9 letter will at the Correct Address??