Divide the 12 hour clock in 3 parts such tat summation of 3 parts must be equal

• I think Parts of clock should be properly divided as per number position on clock.
  
  1,2,11,12...; sum =26
  3,4,9,10; sum =26
  5,6,7,8; sum =26
• 10 years agoHelpfull: Yes(4) No(0)
• WE KNOW THAT (1+2+3+4+5+6+7+8+9+10+11+12)= 78 (COMPLETE CLOCK CYCLE)
  NOW U HAVE TO divide 78 INTO 3 PARTS i.e. 36*3
  so 1st part= (1+2+12+11)= 36
  2nd part= (3+4+10+9)= 36
  3rd part= (5+6+7+8)= 36 hence proved
  
  /"""12""""""
  11 1 /
  / 10 ________2/
  __9______ 3/
  8 _______4/
  7 5
  6
• 10 years agoHelpfull: Yes(1) No(2)
• the numbers in each partition must be continous.. like after 12,1,2,3,.. should... u shouldn't select numbers randomly..
  
• 10 years agoHelpfull: Yes(1) No(0)
• 12+7+4+3=26
  11+8+5+2=26
  10+9+6+1=26
• 10 years agoHelpfull: Yes(0) No(2)
• first part 11+12+1+2=26
  second part=10+9+7=26
  third part=8+3+4+5+6=26
• 10 years agoHelpfull: Yes(0) No(1)
• 11,12,1,3....sum=26
  10,9,7....sum=26
  3,4,5,6,8......sum=26
• 10 years agoHelpfull: Yes(0) No(0)